Indlela ukwehlisa ingxenyenamba ngaphandle wokubala

Izwe yobuchwepheshe okusezingeni eliphezulu predisposes ukuqinisekisa ukuthi abantu abasebenza ngaphansi. Ngenxa yalesi sizathu, ke kwakuqala ukwanda elikhulu amasevisi ukudla okusheshayo, naphezu kwalokho okubonakala kusobala umonakalo ukudla okunjalo ngoba umzimba. ukutholakala Internet kuye kwenza kwaba inqubo yokufunda akuyona indlela kwaba ngaphambi. Manje, ukuxazulula inkinga eziyinkimbinkimbi, vele uye search engine ethandwayo bese ufaka ingxenye umsebenzi ebhokisini lokusesha. Ngenxa yalokho break ezenziwe umuntu wonke umphakathi uqala kancane kancane zilulaza.

Abantu abaningi namuhla ngeke bakwazi ukuchaza izingane zabo indlela yokunciphisa ingxenyenamba, ikakhulukazi uma akusiwona imisebenzi aphansi kanye nezinombolo. Ingasaphathwa amafomula Trigonometric nezenzo. Thina akudingeki uhlale imizuzu emihlanu ukukhumbula okwenzeka esikoleni. Futhi ngeke babe ngisho yokuthi singakwazi lucidly ukuchaza lokho uzokwazi ukukhumbula.

amafraktjhini okungafanele kanye nenguquko zabo

A ingxenyenamba, le numerator zazo inani layo mkhulu zihilela libizwa okungajwayelekile. Ukugqamisa ikhomponethi lonke, engxenyeni engenhla ingxenyenamba ezohlukaniswa phansi. I quotient we eqoshiwe ngokwehlukana futhi okusele ibekwa numerator. Denominator kulokhu zihlala zinjalo.

Izingxenyana eziguquguqukayo

Esimweni lapho bobabili numerator kanye Iningi we ingxenyenamba iqukethe incwadi, ukunciphisa yayo imi kanje:

1. Uma izinhlamvu zihlukile, ungaya nokuncipha izinombolo:

2a / 4c = a / 2c

2. Uma eziguquguqukayo efanayo:

3as / 7skh = 3a / 7x

3. Esimweni lapho kukhona eziningi degrees ke okufanayo isisekelo ingxenyenamba kwenzeka ngokunciphisa ukukhupha ngokuya nenkanyiso encane:

^{7/3 12 = 3 3 0} /3 12-7 = 1/3 5

4. Lesi senzo kwenziwe ezimweni lapho ngezinga elithile variable:

futhi ¹² kuya ^ku-3 / a = ⁵ kuya ^ku-10 futhi ^12-10 / k = ^3/5 futhi ² / k ²

Esimweni lapho lezisekelo zihlukile, akunakwenzeka ukunciphisa ingxenyenamba.

Izingxenyana equkethe izinkulumo

Indlela ukwehlisa ingxenyenamba, le numerator zazo yinani noma umehluko? Esimweni esinjalo kubalulekile ukusebenzisa ifomula emelela ukubuyabuyelela noma ukusakaza Inkulumo factorization. Kuwufanele ukukhumbula ukuthi numerator inani okungenzeka unqanyulwe kuphela endabeni nje kwaqondana ngokuphelele nayo zifana:

(A h +) / (a h +) ² = 1 / (a h +) kanye (a h +) / a = a / a + k / k = a / 1 +

Ngokwesibonelo, indlela yokunciphisa ucezu ifomu:

(4k + ² 4kr + p ²⁾ / (2k + p)

Ukuze afeze nokwehla Usebenzisa square ephambene ifomula isamba kule numerator kanye sithola:

4kr 4k + ² + p ² = (2k + p) ²

Manje ukuthi numerator kanye Iningi ziyafana, siphoqelekile, indlela yokunciphisa ingxenyenamba:

(2k + r) ² / (2k + p) = (2k + p) / 2k +1 = p

Ukuze kalula ukunciphisa ingxenyenamba, kumele ube ujwayelene kanye nekhono ukusetshenziswa amafomula zokuphindaphinda ezifingqiwe. Kwabaningi, lokhu kubonakala kuyinkinga enkulu, kodwa njalo bajwayele basuke ngokuphelele egcinwe. Kutfutfukisa ubuchopho bomuntu, omfundisa ukubona ikhambi izinkinga eyinkimbinkimbi.

indlela enhle yokugcizelela indlela yokunciphisa ingxenyenamba, futhi ukwehlukana kwayo. Lokhu kukuvumela ukuba bavumela ukubuswa lokudala ingxenye, kanye bokusungula. Uma sinquma baphoqa izingane zabo ukuba lezi zibonelo ngokwakho, ukuze sikwazi ukuzisiza ukuzivumelanisa ngokushesha ezishintshayo kanye ematfuba ezingalindelekile zokuphila.