Indlela esibala ngayo imali zemizimba njalo weJiyomethri

Kuyo yonke ezimpilweni zethu njalo kufanele abale ivolumu ezakheke ehlukahlukene Jomethri. Ngokwesibonelo, e-ukwakhiwa kudingekile ukubala kahle inani emiseleni ayecashe kuyo futhi imigodi. Ngaphezu kwalokho, lesi silinganiso kunqunywa cishe zonke Abaklami emsebenzini. Nge ukudlula yoke ikharikhyulamu ku "Jiyomethri" unikeza imininingwane mayelana nendlela abale ivolumu lezinombolo ehlukahlukene Jomethri. Kodwa kuthiwani ngalabo asenesikhathi eside ukhohliwe mayelana wesikole? Lesi sihloko sizokusiza ukukhumbula konke.

Sicela uchaze ukuthi ukubala ivolumu zemizimba njalo weJiyomethri. Lezi zihlanganisa isivivane, a cuboid, ikhoni, isilinda, indulungu ibhokisi.

Isivivane kuyinto polyhedron kabani base kuyinto ipholigoni. Zonke phesheya - aboncantathu nge vertex ezivamile. Ukuze anqume inani umzimba weJiyomethri ezifana, odinga ukukwazi noma ukubala lokungcolisa futhi ukuphakama. Umthamo mbhoshongo kumelwe ilingane ingxenye yesithathu lomkhiqizo ukuphakama futhi indawo sibalo isisekelo. Ngo ifomula kwakuyoba libukeke kanje:

V = 1/3 • S • h

Okulandelayo kuhla lwethu kuyinto ibhokisi. Kanjani ukubala ivolumu kwalesi sibalo? Kuvela ibhokisana - a nezibhebhe elisemandleni ngasesinqeni se a parallelogram. Uma zonke izinhlangothi ezine, ukubizwa ngokuthi i-lateral, kuyinto isikwele ke ibhokisi enjalo ibizwa ngokuthi oqondile. Uma zonke izinhlangothi eziyisithupha - iinkwere, kuba cuboid. Umthamo lesi sibalo oluhambisana umkhiqizo nenani ezimbili: base endaweni futhi ukuphakama sibalo. Ngo ifomula lokhu singatlolwa bunjesi:

V = S • h

Njengoba for ivolumu ye cuboid, kulinganiselwa njengoba umkhiqizo ubude bayo, ububanzi nobude.

V = a • b • h, lapho

futhi - ububanzi, b - izibalo ukuphakama - ubude, h.

Ngu izibalo ezilula osebenza Isigaxa, okuyinto etholakala ngenxa ukujikeleza unxantathu kokuba engela eduzane omunye cathetus yayo. Kanjani ukubala ivolumu Isigaxa? Impela wamane, it ihambelana okwesithathu umsebenzi endaweni base futhi ukuphakama.

V = 1/3 • S • h

Ngaphezu kwalokho, umthamo Isigaxa ingabalwa by ifomula:

V = 1/3 • f • h • r², lapho

n = 3.141592,

r - engaba umbuthano elele base.

Futhi manje sibheke indlela ukubala ivolumu uMbhalo? Khumbula ukuthi uyisihluthulelo. Lolu dengezi - sibalo okuyinto etholakala ngenxa ukujikeleza isikwele mayelana eyodwa ezinhlangothini zalo. Ubukhulu bayo oluhambisana umkhiqizo ukuphakama futhi indawo base. Ifomula kulotshiwe kanje:

V = n • R² • h.

Sphere kuyinto ukuma avaliwe, lapho bonke amaphuzu ugesi walo zitholakala endaweni elifanayo ukusuka enkabeni. Indlela ukubala inani unomzimba onjalo? Ukuze wenze lokhu, kukhona le ndlela elandelayo:

V = 4/3 • 3,14 • r³

Njengoba ubona ngenhla, ukubala ivolumu yimuphi umzimba weJiyomethri ngeke kube nzima, ngoba bayazi ifomula. Uma ngabe inani ku-formula akwaziwa, kubalulekile ukubala, ucabangela kakade isidingo sibalo flat.

Ngaphezu kwalokho, kufanele kuphawulwe ukuthi wonke amanani isicelo ifomula elilodwa kumele inikezwe amayunithi alinganayo. Ngokwesibonelo, uma engaba lubonakaliswa amamitha, futhi ukuphakama futhi kufanele luboniswe amamitha, kungenjalo impendulo kuyoba zamanga.

Ngaphezu kwalezi zeJiyomethri, kukhona bobunjwa eziyinkimbinkimbi: mbhoshongo incishisiwe, isilinda eziyize, nabanye. Kumelwe ukuthi ukhona umthombo nezinye amafomula. Ngokwesibonelo, ivolumu uMbhalo eziyize ilingana umehluko ivolumu uMbhalo amaningana amakhulu namancane. Lapho kubalwa lezi idatha, akukho nzima. Udinga nje ulithumele emzimbeni futhi omunye isinqamu okuyinto siqede. Uzobona ukuthi ikhambi udaba kuyofika ngokwalo. Futhi ningadikibali uma into akusebenzi ukuxazulula, nje qinisekisa ukufunda lesi sihloko.